dy/dx = 2x
f(x, y, z) = x^2 + y^2 + z^2
where C is the constant of integration.
1.2 Solve the differential equation:
A = ∫[0,2] (x^2 + 2x - 3) dx = [(1/3)x^3 + x^2 - 3x] from 0 to 2 = (1/3)(2)^3 + (2)^2 - 3(2) - 0 = 8/3 + 4 - 6 = 2/3 dy/dx = 2x f(x, y, z) = x^2
Solution:
∫(2x^2 + 3x - 1) dx